basic
The three perfume ads featuring
singers from three different genres of music brought varying results.
In order to explain the findings several tests were conducted.
They are as follows: paired t-test, between groups t-test, chi-squared
significance test, frequency, and two simple correlation tests.
Problem One: Paired t-test
Comparing Brand Index Scores
Table A: Brand Index Score
|
Mean
Brand Index Score |
Standard
Deviation |
t-ratio |
Shania
|
30.2 |
7.5 |
.43 |
Belong |
29.9 |
7.4 |
3.44* |
In
Control |
26.1 |
8.2 |
3.71* |
Sample Size = 60
*p ≤ .15
This table represents the Brand Index Scores for the three brands
tested. It proves that Shania by Shania Twain has the highest
mean for Brand Index Score at 30.2. Therefore it can be said that
respondents prefer it to the other two brands. Table A also shows
the t-ratios. Belong by Celine Dion and In Control by Britney
Spears are statistically significant, which means the answers
in the sample can be projected onto the population. In 85 or more
samples out of every 100 samples drawn from the same population
as this sample it would be expected that the Mean Brand Index
Score for Belong and In Control would be about the same as this
sample. However, answers given for Shania can’t be projected
onto the population because it is not statistically significant.
Problem Two: Between Groups
t-test Comparing In Control Movers
Table B: Brand Index Scores
for In Control
|
Sample
size |
Mean
Brand Index Score |
Standard
Deviation |
t-ratio |
Up
Movers |
13 |
29.6 |
6.3 |
.96 |
Down
Movers |
13 |
27.7 |
3.6 |
Table C: Advertising Index
Scores for In Control
|
Sample
size |
Mean
Ad Index Score |
Standard
Deviation |
t-ratio |
Up
Movers |
13 |
4.2 |
3.9 |
.06* |
Down
Movers |
13 |
6.2 |
2.3 |
*p ≤ .15
Table B shows that 13 respondents
reacted positively to the ad for In Control and gave it a higher
score after seeing said ad. Also 13 respondents out of the 60
in the sample had a negative reaction to the ad and dropped their
scores accordingly. The results for the Brand Index Score can’t
be projected onto the population because they are not statistically
significant.
Table C demonstrates the
Advertising Index Score for In Control where out of a sample size
of 60, 13 respondents reacted positively and are subsequently
called up movers. At the same time 13 respondents exhibited a
negative opinion and are referred to as down movers. In 85 or
more samples out of every 100 samples drawn from the same population
as this sample it would be expected that the Mean Ad Index Score
for In Control would be about the same as this sample.
Problem Three: Chi-Squared
Significance Test of Shania Movers
Table D: Chi-Squared Test-Shania
|
Above
Median |
Below
Median |
Sample Size=60
Median Score = 30.5
Chi-Squared Score
= 20.9* |
Up |
Count:
2
Row: 18.2%
Column: 6.7%
Total: 3.3% |
Count:
9
Row: 81.8%
Column: 30%
Total: 15% |
Same |
Count:
8
Row: 30.8%
Column: 26.7%
Total: 13.3% |
Count:
18
Row: 69.2%
Column: 60%
Total: 30% |
Down |
Count:
20
Row: 87%
Column: 66.7%
Total: 33.3% |
Count:
3
Row: 13%
Column: 10%
Total: 5% |
*p ≤ .15
In Table D, only 2 out
of 60 (sample size) moved up in their opinion of Shania perfume
and was above the median of 30.5. This means that after they viewed
the Shania ad in the survey the respondents increased the points
awarded to the Shania brand and the sum of their scores resulted
above the median. A large 87% went down on their opinion of Shania
perfume upon seeing the ad (20 respondents) but remained above
the median making up 66.7% despite the negative feelings. Three
respondents had a negative reaction and brought their division
of points down for the brand and stayed below the median score.
Eighteen of the respondents didn’t change their points for
Shania (30%) and also were reported below the median. In the sample,
eight respondents remained the same for the brand and kept above
the median where nine increased opinion of Shania and were below
the median.
The Chi-Squared score is
statistically significant (20.9*) and therefore can be concluded
that the responses for this survey can adequately be projected
onto the population which this sample was derived. In 85 or more
samples our of every 100 samples drawn from the same population
as this sample it would be expected that the movers who changed
their minds according to the median for Shania would be about
the same as it shows in this sample.
Problem 4: Frequency of
Pre-Exposure and Post-Exposure for Each Brand.
Table E: Mover Count for
Three Brands
|
Shania |
Belong |
In
Control |
Up
Movers |
11 |
18 |
13 |
Same |
26 |
31 |
34 |
Down
Movers |
23 |
11 |
13 |
Sample Size = 60
This table demonstrates
the number of respondents out of the total sample which moved
up, down, or remained the same in their scoring after viewing
the ads for each brand. The opinion of Shania was changed by 23
people who went down on their scoring, while 11 and 13 changed
their mind negatively on Belong and In Control respectively. The
majority of the respondents remained the same in each brand evaluation.
In Control has the highest with 56.7% keeping their division of
scores the same and Shania the lowest with 43.3%. Belong by Celine
Dion had 31 respondents remain the same and 30% of the respondents
changed their mind favorably towards the brand. In Control had
13 respondents (21.7%) move up after viewing the ad and Shania
has 11 (18.3%) move up.
Problem Five: Frequency
of Brand Index Score for Shania vs. In Control
Shania proved to have an
overall higher Brand Index Score than In Control by Britney Spears.
Out of the sample size of 60 respondents, 44 were more favorable
to Shania by Shania Twain and only 16 for In Control. This is
73.3 % preferred Shania over 26.7% for In Control according to
the Brand Index Scores which was a sum of the Likert questions
in the survey.
Problem Six: Simple Correlation
between Belong and In Control
Table F: Correlation of
Brand Index Scores
|
Correlation
Coefficient |
Belong_In
Control |
.4* |
Sample Size = 60
*p
≤ .15
Table F shows that Belong
by Celine Dion and In Control by Britney Spears are moderately
correlated. It is also shown to be statistically significant and
therefore can be assumed the judgements of the sample are connected
to those of the population from which the sample was derived.
In 85 or more samples our of every 100 samples drawn from the
same population as this sample it would be expected that Belong
would be fairly moderately correlated to the brand In Control
as it shows the same in this sample.
Problem Seven: Simple Correlation
between Belong and In Control among daily perfume
users.
Table G: Correlation of
Brand Index Scores of Only Perfume Using Respondents
|
Correlation
Coefficient |
Belong_In
Control |
.4* |
Sample Size = 60
*p ≤ .15
During the survey, respondents
were asked to tell how many times a day they used perfume. If
they answered zero(0) then they were eliminated from the sample
for this particular correlation test. When the variable is taken
out Belong and In Control still have a very moderately correlated
Brand Index Score. It is slightly higher at .428 rather than the
.408 of total respondents in the sample. This too is statistically
significant. In 85 or more samples our of every 100 samples drawn
from the same population as this sample it would be expected that
Belong would be fairly moderately correlated to the brand In Control
as it shows the same in this sample.
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regression
A linear regression analysis
was run on each of three brands of perfume: Shania, Belong, and
In Control. The results are to determine if the 10 Likert items
presented in the survey were positively or negatively related
to the brand through a scatter plot. The results are derived from
the pre-advertisement viewing minus the post-advertisement viewing
scores known as the “change” score. This will conclude
whether people who enjoyed the advertisements also enjoy the brand
by comparing the Likert items (independent variable) against the
change score (dependent variable)
Shania by Shania Twain
Analysis
Table A
R |
R-squared |
Standard
Error of the Estimate |
F |
.7 |
43.8% |
1.0 |
4.13* |
*p≤.15
Table B
Likert Items |
Unstandardized
Coefficient |
Beta |
t-ratio |
Constant |
.1 |
|
.17 |
Shania
is a good brand of perfume. |
-.8 |
.8 |
2.73* |
I
don’t care for the smell of Shania perfume. |
.5 |
.4 |
1.95* |
Shania
perfume is too expensive. |
.6 |
.5 |
2.05* |
Shania
perfume is better than the other perfumes. |
-.3 |
.3 |
1.01 |
Shania
by Stetson is a brand I trust. |
.3 |
.3 |
1.69* |
Using
Shania makes me feel sexy. |
-.2 |
.1 |
.48 |
I
would use Shania. |
-.4 |
.4 |
1.35 |
Shania
gives me confidence. |
.1 |
.0 |
.17 |
Shania
is not like any other perfume. |
-.0 |
.0 |
.06 |
I
would use Shania everyday. |
.1 |
.1 |
.49 |
*p≤.15
Table A gives us the information
that there is a moderate to high correlation (.7) between Shania
and the Likert items that show how well the respondents agreed
with the brand but a not very high percentage to show that correlation
(43.8%). The standard error of the estimate (1.0) has an inverse
relationship with the R and R-squared, therefore it has a relatively
low error because the explain variance is moderately high. The
F-ratio is to test the multiple R(R²) and is statistically
significant (4.13*). In 85 or more samples out of every 100 samples
drawn from the same population as this sample it would be expected
that the change score for Shania would be about the same as this
sample.
Table B explains the line
that would be drawn around the points on the scatter plot. The
unstandardized coefficient is the slope (.1) so it is a positive
upward line with a slight degree of slant. The remaining unstandardized
coefficients are the dots plotted and if they are negative they
are in the negative grid below the x-axis. Betas are the standardized
coefficients and important in explaining the correlation of the
change score. Those listed in bold are of relative importance:
.8(good), .4(smell), .5(price), .4(use). T-ratio is the F-ratio
to test “a” and “b’s” or the dependent
variable and independent variables which some are noted to be
statistically significant. In 85 or more samples out of every
100 samples drawn from the same population as this sample it would
be expected that the change score for Shania would be about the
same as this sample.
Belong by Celine Dion Analysis
Table A
R |
R-squared |
Standard
Error of the Estimate |
F |
.4 |
19.6% |
1.4 |
1.29 |
Table B
Likert Items |
Unstandardized
Coefficient |
Beta |
t-ratio |
Constant |
-.4 |
|
.67 |
Belong
is a good brand of perfume. |
-.6 |
.5 |
1.43 |
I
don’t care for the smell of Belong perfume. |
.8 |
.6 |
2.18* |
Belong
perfume is too expensive. |
.6 |
.4 |
1.32 |
Belong
perfume is better than the other perfumes. |
-.3 |
.2 |
.63 |
Belong
by Celine Dion is a brand I trust. |
.4 |
.3 |
.88 |
Using
Belong makes me feel sexy. |
-.1 |
.1 |
.24 |
I
would use Belong. |
-.4 |
.3 |
.86 |
Belong
gives me confidence. |
.3 |
.2 |
.68 |
Belong
is not like any other perfume. |
-.2 |
.2 |
.47 |
I
would use Belong everyday. |
-.1 |
.1 |
.34 |
*p≤.15
In Table A there is 19.6%
of variance in the dependent variable explained by the independent
variables shown in R². The correlation coefficient (R) is
.4 which is a moderate correlation and thus signifies the standard
error of the estimate to be moderate at 1.4. These terms show
that most respondents either didn’t have a strong opinion
(negative or positive) of Belong or didn’t voice their opinions
in the Likert questions. The F-ratio is an inferential statistic
however it is not statistically significant at 1.29.
The constant in Table B
reveals a negative slope (-.4) so the line on the scatter plot
would show a downward angle. The remaining unstandardized coefficients
point out the other dots on the graph with the standard error
from Table A demonstrating the average (mean) distance from the
line in which the dots would be found. There are several important
betas or standardized coefficients including: .5(good), .6(smell),
.4(price), .3(trust), .3(use). Only one t-ratio is statistically
significant meaning that in 85 or more samples out of every 100
samples drawn from the same population as this sample it would
be expected that the change score for “I don’t care
for the smell of Belong perfume” question on the survey
would be about the same as this sample. Having only seen the advertisement
a respondent might not be able to make a valid response to this
question if it had not be sampled so the results can be projected
onto the population.
In Control by Britney Spears
Analysis
Table A
R |
R-squared |
Standard
Error of the Estimate |
F |
.3 |
7.4% |
1.4 |
.43 |
There is a very low percentage
(7.4%) showing the weak correlation (.3) explaining the relationship
between In Control perfume and the Likert items in the survey.
It is not statistically significant and can’t be projected
to the population. The standard error of the estimate is the mean
distance of respondents away from the regression equation line.
It’s high in accord to the data and thus bad because the
explain variance is low and it goes back to their inverse relationship.
The In Control change score
reads: -.2+.0(good)+.5(smell)-.3(price)-.2(better)-.1(brand)+.0(sexy)-.3(in
control)+.2(confident)+.1(not)+.1(day)
There are four standard
coefficients that are important in explaining the correlated change
score. The Betas are .4(smell), .3(price), .3(in control), .2(confident).
All of the Betas and t-ratios are found in the following table.
Table B
Beta |
|
.0 |
.4 |
.3 |
.1 |
.1 |
.0 |
.3 |
.2 |
.0 |
.1 |
t-ratio |
.34 |
.07 |
1.6* |
.89 |
.39 |
.32 |
.00 |
1.08 |
.47 |
.21 |
.35 |
*p≤.15
The t-ratio which tests
the dependent variable (change score) and independent variables
(Likert items) shows one statistically significant (1.6, smell).
In 85 or more samples out of every 100 samples drawn from the
same population as this sample it would be expected that the “I
don’t like the smell of In Control perfume” would
be about the same as this sample. If the respondent had not tested
the perfume before the smell can not be determined from the advertisement
and would more than likely have resulted in a “neither agree
nor disagree” response with no strong feeling towards either
end of the Likert scale. Thus, the answer to this particular question
can be projected on to the population from which this sample was
derived.
top
discriminant
In the essence of finding
the target audience for In Control by Britney Spears brand of
perfume a Linear Discriminant Analysis was performed. The independent
variables consisted of the 10 Likert items for this brand and
the dependent variable was the “up” or “down”
movers. All respondents who stayed the same in their opinion of
the brand pre- and post- ad viewing were ignored for this analysis.
There was an equal number of “up” movers to “down”
movers in this sample for In Control.
Table A: Likert Items –
Up Movers
|
Mean |
Standard
Deviation |
In
Control is a good brand of perfume. |
3.5 |
.8 |
I
don’t care for the smell of In Control perfume. |
3.5 |
.7 |
In
Control perfume is too expensive. |
3.4 |
.5 |
In
Control perfume is better than the other perfumes. |
3.2 |
.9 |
In
Control by Britney Spears is a brand I trust. |
3.2 |
.9 |
Using
In Control makes me feel sexy. |
3.2 |
.8 |
I
would use In Control. |
3.3 |
.9 |
In
Control gives me confidence. |
3.2 |
.8 |
In
Control is not like any other perfume. |
0.0 |
.0 |
I
would use In Control everyday. |
3.2 |
1.0 |
Sample Size = 13
Group Centroid = .7
Table B: Likert Items –
Down Movers
|
Mean |
Standard
Deviation |
In
Control is a good brand of perfume. |
3.3 |
.5 |
I
don’t care for the smell of In Control perfume. |
3.0 |
.4 |
In
Control perfume is too expensive. |
3.2 |
.4 |
In
Control perfume is better than the other perfumes. |
2.9 |
.6 |
In
Control by Britney Spears is a brand I trust. |
3.1 |
.6 |
Using
In Control makes me feel sexy. |
2.9 |
.8 |
I
would use In Control. |
3.4 |
1.0 |
In
Control gives me confidence. |
3.0 |
.6 |
In
Control is not like any other perfume. |
0.0 |
.0 |
I
would use In Control everyday. |
2.9 |
1.0 |
Sample Size = 13
Group Centroid = -.7
Tables A and B show us
the Mean and Standard Deviation for each of the Likert items asked
on the survey for the respondents who moved up in their opinion
of In Control via the ad shown and those who moved down, respectively.
The sample size for each of these was 13 out of the total of 60
which means that 13 moved up and 13 moved down and the majority
(34) stayed the same on their opinion.
Table C: Wilks’ Lambda
and Chi-Squared
Wilks’
Lambda |
Chi-Squared |
.68 |
7.61 |
The Wilks’ Lambda
measures the significance of the group centroids (found under
Table A and B) in relation to the population in which the sample
was derived. This table is used to project the sample data onto
the population, however the Chi-Squared is not statistically significant
and so the data from the sample can’t be inferred onto the
population. The Group Centroids (.7 and -.7) are the averages
of the dependent variables or z-scores.
Table D: Discriminant Function
Coefficients
|
Standardized |
Unstandardized |
In
Control is a good brand of perfume. |
-.3 |
-.5 |
I
don’t care for the smell of In Control perfume. |
1.1 |
2.1 |
In
Control perfume is too expensive. |
-.3 |
-.6 |
In
Control perfume is better than the other perfumes. |
-.3 |
-.4 |
In
Control by Britney Spears is a brand I trust. |
.4 |
.4 |
Using
In Control makes me feel sexy. |
.5 |
.6 |
I
would use In Control. |
-1.1 |
-1.2 |
In
Control gives me confidence. |
.0 |
.0 |
In
Control is not like any other perfume. |
.0 |
.0 |
I
would use In Control everyday. |
.8 |
.8 |
Discriminant Function Coefficients
are the Likert items from the survey. The important standardized
and unstandardized discriminant function coefficients are in bold
to show the difference in up and down movers. These were determined
significant by taking the absolute value of the highest coefficient
and dividing by 2. If the number was larger than the outcome then
it is deemed important. The unstandardized coefficients are the
“b’s.”
Table E: Classification
Results
Actual
Group |
Predicted
Group |
|
Up |
Down |
Up |
10 |
3 |
Down |
2 |
11 |
Table E shows the number
of respondents who were predicted to be up movers and actual were
up movers (10) and the same for the down movers (11). It’s
near perfect because only 2 or 3 were out of place in the prediction
to what actually happened. Ten people were correctly predicted
to be up movers and 11 people were correctly predicted to be down
movers. The classification matrix states 80.8% of original grouped
cases were correctly classified. [10+11=21/26=.808, where 26 is
the number of cases considered up or down movers.]
Lastly, for the Discriminant
Analysis is an inferential statistic. The t-ratio to test classification
accuracy must be hand calculated as follows:
t-observed data =√[(.808)(.192)/60] + [(.5)(.5)/60]
= √[.003] + [.004]
= √[.007]
= .08
Since this t-ratio measure
the accuracy of the classification matrix (80.8%) it can be proved
statistically significant if the t-observed data is ≥ 1.04.
This being false the classification matrix can’t be projected
onto the population.
In conclusion, this is
not a good discriminant analysis from many factors. The group
centroids are close and the Wilks’ Lambda is not statistically
significant which says this sample can’t be projected onto
the population. The means for the two groups of Likert items are
very close in number as well, which doesn’t conclude a strong
connection on how well respondents perceive the brand. The classification
results were strong and the groups had hardly any mixing, but
are not statistically significant either. The rest of the analysis
doesn’t show a good example from the population and only
slightly discriminates.
top
anova/manova
ANOVA
An analysis of variants, ANOVA, is where
two or more independent variables are compared with one dependent
variable. The independent factors were the move scores for Up,
Down, and Same as well as Region split into East and West. The
dependent factor was from the Likert question: Britney Spears
is not a brand I trust. The test was conducted in order to find
any significant relationship between the variables; such as if
respondents didn’t respond well because they don’t
like Britney Spears not necessarily the ad and if the part of
the country makes a difference. The sample size was 60 and near
even split across the country with 29 from the West and 30 from
the East assuming one person didn’t answer the question.
Table A: Descriptive Statistics
|
Up
Movers |
Same
|
Down
Movers |
West |
Sample |
6 |
Sample |
17 |
Sample |
6 |
Mean |
2.8 |
Mean |
3.2 |
Mean |
3.2 |
Standard
Deviation |
.8 |
Standard
Deviation |
1.4 |
Standard
Deviation |
.8 |
East |
Sample |
7 |
Sample |
16 |
Sample |
7 |
Mean |
3.6 |
Mean |
2.8 |
Mean |
3.0 |
Standard
Deviation |
1.0 |
Standard
Deviation |
1.1 |
Standard
Deviation |
.6 |
The data previously stated
shows the majority of respondents in East and West stayed the
same and equal numbers moved up or down. The overall mean score
for the East is slightly higher than the West but the numbers
are all reflective and therefore similarly correlate. The highest
mean score were the respondents who changed their score positively
after viewing the ad and who also feel most strongly about the
Britney Spears brand.
Table B: Inferential Statistics
|
Sum
of Squares |
Degrees
of Freedom |
Mean
Squared |
F-ratio |
Move |
.3 |
2 |
.2 |
.12 |
Region |
.0 |
1 |
.0 |
.02 |
Move
by Region (Between Groups) |
3.1 |
2 |
1.6 |
1.28 |
Error
(Within Groups) |
64.9 |
53 |
1.2 |
|
*p≤.15
There is no significant
difference between which region of the country and trusting the
Britney Spears brand. There is also no significance if all boxes
are added together (Move by Region). Therefore the sample can’t
be projected onto the population.
MANOVA
A multivariate analysis (MANOVA) is where two or more independent
variables are compared with two or more dependent variables. The
independent variables stayed the same as in the ANOVA analysis
but the dependent variables included all 10 of the Likert items
in the survey. The sample size and region breakdowns are the same
(60,29,30). This study also tests any significance between variables
so if the manner in which the respondents answered the Likert
questions had anything to do with how the ad was perceived or
which part of the country they reside.
Table C: Descriptive Statistics
|
|
West |
East |
|
|
Up
N=6 |
Same
N=17 |
Down
N=6 |
Up
N=7 |
Same
N=16 |
Down
N=7 |
In
Control is a good brand of perfume. |
Mean
Standard Deviation |
3.2
.8 |
2.9
1.2 |
3.3
.5 |
3.7
.8 |
2.6
1.0 |
3.3
.5 |
I
don’t care for the smell of In Control perfume. |
Mean
Standard Deviation |
3.3
.5 |
3.1
1.1 |
2.8
.4 |
3.6
.8 |
3.1
1.0 |
3.1
.4 |
In
Control perfume is too expensive. |
Mean
Standard Deviation |
3.2
.4 |
3.0
.9 |
3.2
.4 |
3.6
.5 |
3.1
.9 |
3.3
.5 |
In
Control perfume is better than the other perfumes. |
Mean
Standard Deviation |
2.7
.8 |
2.6
1.2 |
2.8
.8 |
3.6
.8 |
2.4
.9 |
3.0
.6 |
Britney
Spears is not a brand I trust. |
Mean
Standard Deviation |
2.8
.8 |
3.2
1.4 |
3.2
.8 |
3.6
1.0 |
2.8
1.0 |
3.0
.6 |
Using
In Control makes me feel sexy. |
Mean
Standard Deviation |
2.7
.5 |
2.8
1.2 |
3.0
1.1 |
3.6
.8 |
2.7
1.1 |
2.9
.4 |
I
would use In Control. |
Mean
Standard Deviation |
3.0
.6 |
2.3
1.6 |
3.2
1.2 |
3.6
1.0 |
2.8
1.3 |
3.6
.8 |
In
Control gives me confidence. |
Mean
Standard Deviation |
3.0
.6 |
2.7
1.0 |
3.2
.8 |
3.4
1.0 |
2.5
.9 |
2.9
.4 |
In
Control is not like any other perfume. |
Mean
Standard Deviation |
.0
.0 |
.0
.0 |
.0
.0 |
.0
.0 |
.3
1.3 |
.0
.0 |
I
would use In Control everyday. |
Mean
Standard Deviation |
2.7
.8 |
2.6
1.3 |
2.8
1.2 |
3.7
1.0 |
2.3
1.3 |
2.9
.9 |
Table C reflects the descriptive
statistics for the analysis of all 10 Likert items versus the
change score for West and East regions of the country. Each cell
shows the mean and standard deviation for the Up, Same, or Down
Movers pre-to-post exposure of the ad for In Control. The sample
size for the West was 6 Up, 17 Same, and 6 Down Movers. The East
sample size was 7 Up, 16 Same, and 7 Down. Overall the mean scores
from the East tended to be slightly higher than those from the
West meaning they felt more positively toward In Control perfume
or the Britney Spears brand.
The second to last question,
In Control is not like any other perfume was left blank by almost
everyone in the survey except respondent(s) from the East who
didn’t change their opinion of the brand after seeing the
ad. The greatest mean score was 3.7 reflecting that respondents
from the East who increased their score after viewing the ad felt
that In Control was a good brand of perfume. The lowest mean scores
accounted for were 2.3 on non-moving respondents both from West
and East who weren’t as sure about using In Control.
Table D: Inferential Statistics
|
Wilk’s
Lambda |
F-ratio |
Move |
.69 |
.90 |
Region |
.83 |
.92 |
Move
by Region
(Between Groups) |
.77 |
.61 |
*p≤.15
In the table the F-ratio
is the determinant if the statistics are significant for the MANOVA
test and can thus be projected onto the population. However as
shown none of the results for Move, Region, or Move by Region
were significant and therefore this sample can’t be projected
onto the population from which it was derived. This was the same
results found in the ANOVA analysis as well.
top
factor
A Factor Analysis is conducted
to make sure a scale is efficient according to EPA (Evaluative,
Potency, Activity). This Factor Analysis will tell which of the
three brands were preferred in regards to their Likert items(like/disklike).
Using the 60 respondents in the sample an attitude score was organized
for each brand based on an attitude scale using the 10 Likert
items of each brand. These were subsequently compared by three
paired t-tests to determine the brand that was perceived in the
highest favorability.
Table A: Communalities
and Factor Matrices for Shania
Likert Items |
Communalities |
Factor
Matrix |
Varimax
Rotated Matrix |
1 |
2 |
1 |
2 |
Shania
is a good brand of perfume. |
.8 |
.9 |
.2 |
.6 |
.7 |
I
don’t care for the smell of Shania perfume. |
.8 |
.7 |
.6 |
.2 |
.9 |
Shania
perfume is too expensive. |
.7 |
.8 |
.3 |
.4 |
.7 |
Shania
perfume is better than the other perfumes. |
.8 |
.9 |
-.1 |
.8 |
.5 |
Stetson
is not a brand I trust. |
.7 |
.7 |
.5 |
.3 |
.8 |
Using
Shania makes me feel sexy. |
.8 |
.9 |
-.3 |
.9 |
.3 |
I
would use Shania. |
.8 |
.9 |
-.2 |
.8 |
.4 |
Shania
gives me confidence. |
.8 |
.8 |
-.4 |
.9 |
.2 |
Shania
is not like any other perfume. |
.5 |
.7 |
-.3 |
.7 |
.2 |
I
would use Shania everyday. |
.7 |
.8 |
-.2 |
.8 |
.4 |
Table B: Total Variance
for Shania
Factors |
Eigenvalues |
%
of Variance |
Cumulative
% |
1 |
6.5 |
65.3 |
65.3 |
2 |
1.0 |
10.1 |
75.4 |
3 |
.7 |
6.7 |
82.1 |
4 |
.5 |
4.6 |
86.7 |
5 |
.4 |
3.5 |
90.2 |
6 |
.3 |
3.0 |
93.2 |
7 |
.2 |
2.4 |
95.6 |
8 |
.2 |
2.0 |
97.6 |
9 |
.1 |
1.4 |
99.0 |
10 |
.1 |
1.0 |
100.0 |
Table B shows us the two
factors that were used in Table A because the first two factors
were the only Eigenvalues greater than or equal to 1 or had the
most explained variance. Table A takes these factors and compares
them by absolute value to determine which factor the Likert item
“loads” on. As the c